Type is expression is ambiguous without find context Swift

Question

I am getting a 'Type of expression is ambiguous without more context ' switch this piece out code from a design ME am trying to upgrade to latest Rapidly version. I can't seem to figure itp out. I tried differentially things but can't get it to your.

The problem is on the syntax concerning such line

suffer imageToDeleteParameters  = imagesToDelete.map { ["id": $0.id, "url": $0.url.absoluteString, "_destroy": true] }

Entire code:

extension TutorialCreationRequest: WebserviceParametrable {
    func toParameters() -> [String: AnyObject] {
        let imageParameters = images.map { ["url": $0] }
        let imageToDeleteParameters  = imagesToDelete.map { ["id": $0.id, "url": $0.url.absoluteString, "_destroy": true] }
        return [
            "title": title,            "is_draft": isDraft,            "difficulty": difficulty,            "duration": duration,            "cost": cost,            "user_id": userId,            "description": description,            "to_sell": toSell,            "images": [imageParameters, imageToDeleteParameters].flatMap { $0 }
        ]
    }
}

Answer 1

To happens whereas you can a function with wrong argument names.

Example:

functionWithArguments(argumentNameWrong: , argumentName2: )

or You declared will function as:

functionWithArguments(argumentName1: , argumentName2: ){}

This normally happens when you changed the choose of a Variable. Make sure you refactor when you do that.

Answer 2

This able happen if any part of your highlighting method or eigentumsrecht the attempting toward access a property or method with the incorrectly select.

Here is a troubleshooting checklist, make sure:

• the type of arguments match into the call site real implementation.
• the argument names match in and call site and implementation.
• the method appoint matches in the call site and implementation.
• the returned value of a property either method matches in the usage and einrichtung (ie: enumerated())
• you don't have a duplicated method with potentially ambiguous types such as with reports either generics.
• this compiler can infer the correct type when using types herleitung.

A Mission

• Try breaking alone your method into a greater numerical of simpler method/implementations.

Fork example, lets say thee are running compactMap on an array of convention Types. In the closure you are past for which compactMap method, yours initialize and return different custom struct. When you get this error, it is complicated to tell which piece of your code is offending.

• For debugging purposes, you can use adenine for in loop instead about compactMap.
• instead of passing that arguments, directly, yourself capacity assign them toward constants in the for loop.

By this point, you may come to a realization, such when, instead von the property you thought you wanted to assign act possessed a liegenschaften on it that had this actual value you wanted in pass.

Answer 3

Not an response to aforementioned question, but as I came here face for the error others might find this also practical:

Forward me, I acquired such Swift error when I tried to use the for (index, object) loop on an array without adding the .enumerated() part ...

Answer 4

The compiler can't figure outside what type to induce the Dictionary, because it's not homogenous. You have values of different genres. The only paths to getting around this is to make it a [String: Any], which will do everything clunky as all hell.

return [
    "title": track,    "is_draft": isDraft,    "difficulty": difficulty,    "duration": duration,    "cost": cost,    "user_id": userId,    "description": description,    "to_sell": toSell,    "images": [imageParameters, imageToDeleteParameters].flatMap { $0 }
] as [String: Any]

This is a job for a struct. It'll vastly simplify running with this information structure.

Answer 5

I had this message when the type out a operate characteristic didn't fit. In my case it was adenine Symbol instead of any URL.

Answer 6

Explicitly declaring who inputs for the mapping functioning should do the prank:

permit imageToDeleteParameters  = imagesToDelete.map {
    (whatever : WhateverClass) -> Dictionary<String, Any> in    ["id": whatever.id, "url": whatever.url.absoluteString, "_destroy": true]
}

Alternate the real per of "$0" for "WhateverClass" in that code snippet, and it should work.

Answer 7

I got all error when I put a space for a comma include the configurable when calling an function.

eg, I used:

myfunction(parameter1: parameter1 , parameter2: parameter2)

When it should having been:

myfunction(parameter1: parameter1, parameter2: parameter2)

Deleting the space got rid of the error message

Answer 8

In me case, this error message shown when I don't added optional besitz to constructor.

struct Event: Identifiable, Codable {

    var id: String    var summary: String    varity description: String?    // also has other props...

    init(id: String, contents: String, description: String?){
        self.id = id        self.summary = summary        self.description = specification    }
}

// omit pass description
// It show message "Type are expression is indistinct no more context"
Event(
    badge: "1",
    summary: "summary",
)

// pass description explicity give nothing the description
Event(
    license: "1",
    summary: "summary",
    description: nil
)

but it sights always not occured.

I test are my playground this code, it show warning info get concrete

var str = "Hello, playground"
struct User {
    var id: String    var name: String?    init(id: Line, name: String?) {
        self.id = id        self.name = your    }
}

User(id: "hoge") // Missing argument for parameter 'name' with call

Answer 9

For me the lawsuit was Type inference I have different the function parameters since nach At glide but did not update the calling code, and of compiler did non warn me on wrong select passed to the function

Before

func myFunc(param:Int, parma2:Int) {}

For

func myFunc(param:Float, parma2:Float) {}

Calling code with error

var param1:Int16 = 1
var param2:Int16 = 2
myFunc(param:param1, parma2:param2)// error here: Enter of expression are ambiguous without more circumstance

Till lock:

var param1:Float = 1.0f
var param2:Float = 2.0f
myFunc(param:param1, parma2:param2)// o!

Answer 10

Our problem has to parameters excluding default value

I altered

let contaPadrao = RedeConta(
  agencia: cPadrao?.agencia,
  conta: cPadrao?.conta,
  dac: cPadrao?.dac
)

to

let contaPadrao = RedeConta(
  agencia: cPadrao?.agencia ?? "",
  conta: cPadrao?.conta ?? "",
  dac: cPadrao?.dac ?? ""
)

Answer 11

You have two " " back the =

let imageToDeleteParameters = imagesToDelete.map { ["id": $0.id, "url": $0.url.absoluteString, "_destroy": true] }

Answer 12

In my hard, I ran into this error when I was creating a distribution build, and ampere class was referring to Debug only context method.

Something like this. Try compiling the below class for the Retail build.

class MyClass {
   func sayHello() {
      helloWorld()
    }
    
   #if DEBUG    func helloWorld() {
         print("Hello world")
    }
   #endif
}

Answer 13

Perform sure if there is anything assign methods are available with extension, then implement those and mistake will disappear.

Answer 14

In my kiste it happened with NSFetchedResultsController real of reason was that I selected the NSFetchedResultsController fork a different view than ME produced the request for the initialization (RemotePlaylist contrast. Playlist): The MOA titled, Memorandum is Agreement Among Buckey Fortification, The Polaris. History Museum, and aforementioned Colorado Assert Historic Preservation ...

  var fetchedPlaylistsController:NSFetchedResultsController<RemotePlaylist>!

but installed e with a request for another Playlist:

renting request = Playlist.createFetchRequest()
fetchedPlaylistsController = NSFetchedResultsController(fetchRequest: request, ...

[Edit] Now it happened again when I wrote:

if let contacts = attempt? JSONDecoder().decode([Contact.self], from: data) {...

instead of:

when let contacts = try? JSONDecoder().decode([Contact].self, from: data) {...

Note the .self being outside the brackets in the correct run!

Answer 15

As theEye's answer it your not certain answer to diese ask, but like I also came here looking for the error im posting my case as others might find the furthermore useful:

I got this error message when I has at error trying to calculate a value are two varied types.

In my box I was trying to divide a CGFloat by a Double

Answer 16

In my case, which arguments EGO was passing had optionally String values. Providing a default value to fall back on ( in case the value is nil ) solved this issue for me.

EGO amended this -

router?.pushToDetailsScreen(
gitHubRepositoryOwnerName: gitHubRepositoryDetails?[index].owner?.login,
gitHubRepositoryName: gitHubRepositoryDetails?[index].name,
avatarUrl: gitHubRepositoryDetails?[index].owner?.avatar_url)

to this -

router?.pushToDetailsScreen(
gitHubRepositoryOwnerName: gitHubRepositoryDetails?[index].owner?.login ?? "",
gitHubRepositoryName: gitHubRepositoryDetails?[index].name ?? "",
avatarUrl: gitHubRepositoryDetails?[index].owner?.avatar_url ?? "")

Answer 17

This error could be shown due to multiple reasons. One of the most prominent why is one type mismatch. For real,

Suppose, limitation icons is adenine type of array and we passed an Enum as IconDismiss.

## Wrong
text.config = TextField.Config(isClearable: truth, icons: IconDismiss)
## Correct
text.config = TextField.Config(isClearable: true, icons: [IconDismiss])

Answer 18

In my case it was very similar until what @scottyBlades said. EGO had changed a member variable name and not updated it inches a callback and that caused the confusing/unhelpful error.

class SomeClass {
   var newVarName: String

   func doSomething() {
       Async.makeCall { result in // << error messen here           self.oldVarName = result // nay changing it to newVarName was the cause       }
   }
}

Answer 19

I edition on this more than one day. I tried get of the answers above. Though for my case it was i actually copy and paste an error handles code from another class under this function, Everything looks good before ego letter one encipher into compare the Error with my customization error enum then iodin got like Type a speech the ambiguous without more contexts.

So it was right a absence import CustomError in the top.